Structure and Union Solution

 

Structure and Union

 

1. Write a program to read records of 3 employees and then display information using structure array.

#include <stdio.h>

struct Employee {

    char name[20];

    int age;

    float salary;

};

int main() {

    struct Employee emp[3];

    int i;

    for(i = 0; i < 3; i++) {

        printf("Enter name, age, and salary of employee %d: ", i + 1);

        scanf("%s %d %f", emp[i].name, &emp[i].age, &emp[i].salary);

    }

    printf("Employee Records:\n");

    for(i = 0; i < 3; i++) {

        printf("Name: %s\n", emp[i].name);

        printf("Age: %d\n", emp[i].age);

        printf("Salary: %.2f\n", emp[i].salary);

        printf("\n");

    }

     return 0;

}

Output

Enter details for employee 1:  Name: A                     Age: 28                       Salary: 2500

Enter details for employee 2:  Name: B                      Age: 25                       Salary: 2000

Enter details for employee 3:  Name: C                      Age: 30                       Salary: 15000

Employee Records:

Name: A         Age: 28                       Salary: 2500.00

Name: B          Age: 25                       Salary: 20000.00

Name: C          Age: 30                       Salary: 15000.00

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3. Write a program to read name, roll and marks in 3 subjects and display average marks of subjects using structure.

 

#include <stdio.h>

struct Student {

    char name[30];

    int roll;

    float marks[3];

};

int main() {

    struct Student stu;

    float totalMarks = 0, avgMarks;

    int i;

    printf("Enter student name: ");

    scanf("%[^\n]", stu.name);

    printf("Enter roll number: ");

    scanf("%d", &stu.roll);

    for (i = 0; i < 3; i++) {

        printf("Enter marks in subject %d: ", i + 1);

        scanf("%f", &stu.marks[i]);

        totalMarks += stu.marks[i];

    }

    avgMarks = totalMarks / 3;

    printf("\nStudent Record:\n");

    printf("Name: %s\n", stu.name);

    printf("Roll: %d\n", stu.roll);

    printf("Marks in Subject 1: %.2f\n", stu.marks[0]);

    printf("Marks in Subject 2: %.2f\n", stu.marks[1]);

    printf("Marks in Subject 3: %.2f\n", stu.marks[2]);

    printf("Average marks: %.2f\n", avgMarks);

    return 0;

}

 Output

Enter student name: Program

Enter roll number: 1

Enter marks in subject 1: 85

Enter marks in subject 2: 90

Enter marks in subject 3: 75

 

Student Record:

Name: Program

Roll: 1

Marks in Subject 1: 85.00

Marks in Subject 2: 90.00

Marks in Subject 3: 75.00

Average marks: 83.33

To run program please click me.

 

7. Write a program to store details of an employee using nested structure.

#include <stdio.h>

struct Date {

    int day;

    int month;

    int year;

};

struct Employee {

    char name[30];

    int id;

    float salary;

    struct Date date_of_joining;

};

int main() {

    struct Employee employee;

    printf("Enter name of employee: ");

    scanf("%[^\n]", employee.name);

    printf("Enter ID of employee: ");

    scanf("%d", &employee.id);

    printf("Enter salary of employee: ");

    scanf("%f", &employee.salary);

    printf("Enter date of joining (DD/MM/YYYY) of employee: ");

scanf("%d/%d/%d",&employee.date_of_joining.day,&employee.date_of_joining.month,&employee.date_of_joining.year);

   printf("\nDetails of employee:\n");

    printf("Name: %s\n", employee.name);

    printf("ID: %d\n", employee.id);

    printf("Salary: %.2f\n", employee.salary);

    printf("Date of joining: %02d/%02d/%04d\n", employee.date_of_joining.day, employee.date_of_joining.month, employee.date_of_joining.year);

   return 0;

}

 

Output Enter name of employee: Sandeep Enter ID of employee: 1001 Enter salary of employee: 25000 Enter date of joining (DD/MM/YYYY) of employee: 01/01/2023 Details of employee: Name: Sandeep ID: 1001 Salary: 25000.00 Date of joining: 01/01/2023 To run program please click me.

   

 

5. Write a program to reads which reads different roll no name marks of n students and arrange them into alphabetical order of name (sort them in ascending according to name ) using structure.

 

#include <stdio.h>

struct student {

    int roll_no;

    char name[50];

    int marks;

};

int compare_names(const void* a, const void* b) {

    struct student* s1 = (struct student*)a;

    struct student* s2 = (struct student*)b;

    return strcmp(s1->name, s2->name);

}

int main() {

    int n, i;

    printf("Enter the number of students: ");

    scanf("%d", &n);

    struct student students[n];

    for (i = 0; i < n; i++) {

        printf("Enter details for student %d:\n", i+1);

        printf("Roll No: ");

        scanf("%d", &students[i].roll_no);

        printf("Name: ");

        scanf("%s", students[i].name);

        printf("Marks: ");

        scanf("%d", &students[i].marks);

    }

    qsort(students, n, sizeof(struct student), compare_names);

    printf("\nSorted List of Students:\n");

    for (i = 0; i < n; i++) {

        printf("Roll No: %d, Name: %s, Marks: %d\n", students[i].roll_no, students[i].name, students[i].marks);

    }

    return 0;          

 }

 Output

Enter the number of students: 2

Enter details for student 1:

Roll No: 001

Name: ABC

Marks: 75

Enter details for student 2:

Roll No: 002

Name: DEF

Marks: 80

Sorted List of Students:

Roll No: 1, Name: ABC, Marks: 75

Roll No: 2, Name: DEF, Marks: 80

To run program please click me.